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In that case, invert the signals going to your LEDs. I’m still getting the same effect. Okay I wired 7,9, and 10 together and then connected them to a 1K resistor to 5V.
(PDF) 74161 Datasheet download
Finally, you should not couhter on TTL outputs driving high, as you have shown. I switched the LEDs around and connected their input to 5V and their ground to the output pins. It’s always the simple things. Get into the habit now. Then I used a pullup resistor for the clear switch.
Post as a guest Name. Since you already need one section of aand there are 6 gates per IC, you simply go.
Sign up using Facebook. Whenever I press the clock button I get all of the leds on except maybe one or two, with some flashing during the button press. Oh, Ill change that and see what happens. Sign up or log in Sign up using Google. So your outputs should be connected like. 741611, have you added a 0. So your outputs should be connected like simulate this circuit — Schematic created using CircuitLab You may object that this will provide LEDs which are on when the output is low, sbeet off when the outputs are high, which is confusing.
Datasheet(PDF) – TI store
I have added a debounce circuit, but still to avail. You can often get away with less, but as you’ve just learned, insufficient decoupling can have weird symptoms. For a circuit board with a ground plane, the usual guideline is at least one cap per 5 ICs.
I’d reduce that down to something in the nF to 1uF range. Home Questions Tags Users Unanswered. You may object that this will provide LEDs which are on when the output is low, and off when the outputs are high, which is confusing.
I added a 0. For breadboards, use a cap for each IC.
Without this buffering, your switch should not work on a button push, only on a release.